Home › NEET UG › Physics › Electric Charges and Fields › Two large parallel conducting plates carry equal…
Two large parallel conducting plates carry equal and opposite surface charge density σ. The electric field BETWEEN the plates is:
Aσ / ε₀
Bσ / (2 ε₀)
CZero
D2 σ / ε₀
Answer & Solution
Correct answer: A. σ / ε₀
1. Each conducting plate, by itself, would give E = σ / (2 ε₀) on EACH side (treat as sheet).
2. Between the plates, the fields ADD (both point from + to −).
3. Total E = 2 · σ/(2ε₀) = σ / ε₀ between the plates.
4. Outside the pair, the two plate fields CANCEL → E = 0.
_Source: NCERT Class 12 Physics Ch 1 §1.10 Parallel-Plate Field_
Related questions
In SI units the constant $k$ in Coulomb's law $F = k\frac{q_1 q_2}{r^2}$ is approximatelyTwo point charges repel each other with force $F$. If the distance between them is doubledAccording to Coulomb's law, the electrostatic force between two point charges $q_1$ and $qEquipotential surfaces are everywhere:An electric field of 1000 V m⁻¹ exists between two parallel plates 4 cm apart. The potentiAn electron (q = −e, mass m) accelerated from rest through a potential difference V gains Torque on a dipole of moment p placed in a uniform field E at angle θ is:An electric dipole consists of charges +q and −q separated by 2a. The dipole moment magnit