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Two large parallel conducting plates carry equal and opposite surface charge density σ. The electric field BETWEEN the plates is:
Aσ / ε₀
Bσ / (2 ε₀)
CZero
D2 σ / ε₀
Answer & Solution
Correct answer: A. σ / ε₀
1. Each conducting plate, by itself, would give E = σ / (2 ε₀) on EACH side (treat as sheet).
2. Between the plates, the fields ADD (both point from + to −).
3. Total E = 2 · σ/(2ε₀) = σ / ε₀ between the plates.
4. Outside the pair, the two plate fields CANCEL → E = 0.
_Source: NCERT Class 12 Physics Ch 1 §1.10 Parallel-Plate Field_
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