A dipole of moment 10⁻²⁹ C·m is placed in a uniform field of 10⁵ N/C a…

Question

A dipole of moment 10⁻²⁹ C·m is placed in a uniform field of 10⁵ N/C at angle 30°. The torque on the dipole is:

Accepted Answer

B. 5 × 10⁻²⁵ N·m (τ = pE sin 30° = 10⁻²⁹ × 10⁵ × 0.5)

We have τ = pE sin θ.
That is τ = (10⁻²⁹) × (10⁵) × sin(30°).
That is τ = 10⁻²⁹ × 10⁵ × 0.5.
So τ = **5 × 10⁻²⁵ N·m**.
At θ = 90°, torque is maximum (pE); at θ = 0° or 180°, torque = 0.

Answer

0

Answer

10⁻²⁴ N·m

Answer

10⁻¹⁹ N·m

A dipole of moment 10⁻²⁹ C·m is placed in a uniform field of 10⁵ N/C at angle 30°. The torque on the dipole is:

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