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A dipole of moment 10⁻²⁹ C·m is placed in a uniform field of 10⁵ N/C at angle 30°. The torque on the dipole is:
A0
B5 × 10⁻²⁵ N·m (τ = pE sin 30° = 10⁻²⁹ × 10⁵ × 0.5)
C10⁻²⁴ N·m
D10⁻¹⁹ N·m
Answer & Solution
Correct answer: B. 5 × 10⁻²⁵ N·m (τ = pE sin 30° = 10⁻²⁹ × 10⁵ × 0.5)
τ = pE sin θ = (10⁻²⁹) × (10⁵) × sin(30°) = 10⁻²⁹ × 10⁵ × 0.5 = **5 × 10⁻²⁵ N·m**. At θ = 90°, torque is maximum (pE); at θ = 0° or 180°, torque = 0.
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