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Inside a uniformly charged conducting sphere (in equilibrium), the electric field is
Athe same as outside: $kQ/r^2$ inward
Bzero everywhere inside the conductor
C$kQ/R^2$, constant
Dexponentially decaying with depth from the surface
Answer & Solution
Correct answer: B. zero everywhere inside the conductor
1. In ELECTROSTATIC EQUILIBRIUM, free charges in a conductor have stopped moving — they've redistributed until they feel no net force.
2. No net force means no net electric field on those charges. Since they're inside the conductor, the field INSIDE must be ZERO.
3. This is true at every interior point of a charged conductor at equilibrium, regardless of shape.
4. Consequence: a hollow conductor SHIELDS its interior from external fields — the basis of a Faraday cage.
5. Option A would be the field outside (and contradicts the equilibrium argument). Option C confuses with the field at the surface. Option D has no physical basis.
_Source: NCERT Class 12 Physics Part 1, Ch 1, §1.14 (Charged conductor — interior field zero), p. 32–33._
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