Home › NEET UG › Physics › Electric Charges and Fields › Using Gauss's law, the electric field due to an …
Using Gauss's law, the electric field due to an **infinite plane sheet of charge** with surface charge density σ is:
AE = σ/(4πε₀r²)
BE = σ/(2ε₀) — **independent of distance from the sheet!**
CE = σr/(2ε₀)
DE = σ/(ε₀r)
Answer & Solution
Correct answer: B. E = σ/(2ε₀) — **independent of distance from the sheet!**
Gaussian cylinder (or pillbox) crossing the sheet, faces parallel to sheet. By symmetry E perpendicular to sheet on both sides. Flux = 2EA = σA/ε₀ → **E = σ/(2ε₀)**. **Independent of distance** — the infinite sheet looks the same from any distance.
Related questions
A charged comb picks up small pieces of paper that carry no net charge, because the paper Compared with the tiny nucleus, the electrons around it form a cloud that is:Benjamin Franklin explained early observations by supposing that one type of charge stayedA test charge or a source charge moves, and as a result the force between them:If the two ends of a dipole can be pulled apart, induction can create charged objects withPlaced in a uniform field, such a dipole experiences a turning effect that changes its angTwo equal and opposite charges separated by a small distance form a dipole, characterised Where those lines are packed more densely, the field is: