alleryThe electric field on the **equatorial line** of a dipole (perpendicular bisector, r >> a) has magnitude:
A2kp/r³
Bkp/r³, direction **antiparallel** to the dipole moment p
Ckp²/r³
Dkp/(r² + a²)^(3/2)
Answer & Solution
Correct answer: B. kp/r³, direction **antiparallel** to the dipole moment p
**Equatorial dipole field at large r**: E = kp/r³ pointing **opposite to p** (because both charge fields contribute components antiparallel to p; the parallel-to-r components cancel by symmetry).
E_eq is **half** of E_axial in magnitude.
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