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JEE Main Rotational Motion — practice questions

40 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.

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The moment of inertia of a solid sphere of mass $M$ and radius $R$ about a diameter is:A particle of mass $m$ moves in a circle of radius $R$ with constant speed $v$. Its angular momentum about theA solid sphere of mass $M$ and radius $R$ rolls without slipping on a horizontal surface with translational spA thin uniform rod of mass $M$ and length $L$ rotates about an axis perpendicular to the rod and passing throuA solid sphere is released from rest at the top of an incline of angle $\theta$. If it rolls without slipping A solid disc and a thin ring, having the same mass and same radius, are released from rest at the top of the sAngular displacement theta in a circular motion is related to arc length s and radius r as:Angular velocity omega in terms of time period T:Linear speed v and angular speed omega relation for circular motion:Torque tau acting on a body produces:Angular momentum L of a body rotating with angular velocity omega:A wheel starting from rest reaches 20 rad/s in 4 s. Angular acceleration alpha:Moment of inertia of a uniform solid sphere of mass M and radius R about an axis through center:Moment of inertia of a thin uniform disc (mass M, radius R) about axis perpendicular to disc through center:Parallel axis theorem states I_parallel = I_cm + Md². Here d is:For a thin rod of mass M and length L, I about axis through center perpendicular to rod:Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:For a body rolling without slipping with velocity v of center of mass:A solid cylinder and a hollow cylinder of same mass and radius roll down an incline. Which reaches bottom firsTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis through center perpendicuA figure skater pulls in her arms during a spin. Her moment of inertia decreases. By conservation of L (I × omFor a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order of acceleration (fasA solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. Acceleration:Two point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis through center perpendicuFor a thin rod (mass M, length L) about axis through ONE END perpendicular to rod, I equals:Torque on a body produces angular acceleration. For tau = 20 N m and I = 5 kg m², alpha equals:A 50 kg flywheel of radius 0.5 m rotates at 60 rev/min. Angular momentum (I = MR²/2):A solid sphere rolls down without slipping. Fraction of KE that is rotational:A man stands at center of a rotating platform with hands extended (I_initial). He brings hands closer to body A wheel rotating at 50 rad/s decelerates uniformly to rest in 10 s. Total angular displacement:Angular acceleration alpha = 4 rad/s² acts for 5 s on a wheel starting from rest. Number of revolutions:For a body rotating at constant angular velocity omega, the linear speed at distance r from the axis is v = omA solid cylinder (I = MR²/2) of mass 2 kg, radius 0.1 m, rolls without slipping at 6 m/s. Total kinetic energyA merry-go-round (I = 1000 kg m²) rotates at 0.5 rad/s. A 50 kg child runs and jumps onto it at radius 2 m. NeFor a solid cylinder rolling without slipping, the friction force at the contact point:Moment of inertia of an annular disc (inner radius r1, outer r2) about perpendicular axis through center:A child pushes a door of width $0.8$ m perpendicular to the door at the handle with $20$ N force. The torque aA solid disc of mass $M$, radius $R$, rotating about its centre axis has moment of inertia:An ice skater spinning with arms outstretched at $\omega_1$ pulls arms in, halving her moment of inertia. Her A bicycle wheel of radius $R$ rolls without slipping at linear speed $v$. The angular speed $\omega$ is: