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A solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. Acceleration:
Ag sin theta
Bg sin theta × (1/3)
Cg sin theta × (5/7)
DZero
Answer & Solution
Correct answer: C. g sin theta × (5/7)
For solid sphere: a = g sin theta / (1 + I/(MR²)) = g sin theta / (1 + 2/5) = g sin theta / (7/5) = (5/7) g sin theta. About 71 percent of pure sliding acceleration.
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