Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:
AI omega
B(1/2) I omega²
CI omega²
D(1/2) I omega
Answer & Solution
Correct answer: B. (1/2) I omega²
KE_rot = (1/2) I omega² (analog of (1/2) m v²). For a body in pure translation: KE = (1/2)Mv². For rolling: total KE = (1/2)Mv² + (1/2)I omega².
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