Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:
AI omega
B(1/2) I omega²
CI omega²
D(1/2) I omega
Answer & Solution
Correct answer: B. (1/2) I omega²
KE_rot = (1/2) I omega² (analog of (1/2) m v²). For a body in pure translation: KE = (1/2)Mv². For rolling: total KE = (1/2)Mv² + (1/2)I omega².
Related questions
The branch describing the motion of a rotating rigid body about a fixed axis is rotationalSix washers on a light rod illustrate the moment of inertia of a system of:The more massive an object is, the more of this it has in linear motion:Unlike linear position measured in metres, angular position is measured in units that are:Acceleration caused by the change in direction of tangential velocity is called:Several torques acting about one axis are combined by finding their:The perpendicular distance from the axis to the line of the force is called the:The SI unit of torque is the newton multiplied by the: