Two point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis through center perpendicular to rod:
A12
B24
C48
D36
Answer & Solution
Correct answer: A. 12
Each mass at distance 2 m from center. I = sum m × r² = 2 × (3 × 4) = 24 kg m². Wait, recompute: 3 × 2² + 3 × 2² = 12 + 12 = 24. So I = 24. Hmm option B says 24 — I should select B.
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