A solid disc of mass $M$, radius $R$, rotating about its centre axis has moment of inertia:
A$MR^2$, treating it like a ring on the rim
B$2MR^2$, doubling the ring case for caution
C$\tfrac{2}{5}MR^2$, the value for a solid sphere on the rod
D$\tfrac{1}{2}MR^2$, the standard result for a uniform disc
Answer & Solution
Correct answer: D. $\tfrac{1}{2}MR^2$, the standard result for a uniform disc
A uniform disc about its central axis: $I = \tfrac{1}{2}MR^2$.
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