Moment of inertia of a thin uniform disc (mass M, radius R) about axis perpendicular to disc through center:
AMR²/2
BMR²
CMR²/3
DMR²/4
Answer & Solution
Correct answer: A. MR²/2
For a thin disc about perpendicular axis through center: I = MR²/2. (About diameter: I = MR²/4 by perpendicular-axis theorem.)
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