alleryFor a body rolling without slipping with velocity v of center of mass:
Aomega = v R
Bomega = 0
Cv = omega R (R = radius)
Dv = R/omega
Answer & Solution
Correct answer: C. v = omega R (R = radius)
Rolling without slipping: contact point of body with ground is instantaneously at rest, so v = omega × R for the center.
Keep practising Unit 1C: Kinematics: Relative & Circular Motion
Browse all Unit 1C: Kinematics: Relative & Circular Motion questions for AP Physics 1, or explore more Physics topics.
Related questions
A solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. For a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order A figure skater pulls in her arms during a spin. Her moment of inertia decreases. By conseTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis throuA solid cylinder and a hollow cylinder of same mass and radius roll down an incline. WhichKinetic energy of a rotating body with moment of inertia I and angular velocity omega:For a thin rod of mass M and length L, I about axis through center perpendicular to rod:Parallel axis theorem states I_parallel = I_cm + Md². Here d is: