alleryA 50 kg flywheel of radius 0.5 m rotates at 60 rev/min. Angular momentum (I = MR²/2):
A20 kg m²/s
B314 kg m²/s
C39.3 kg m²/s
D3.14 kg m²/s
Answer & Solution
Correct answer: C. 39.3 kg m²/s
We have I = (1/2) × 50 × 0.5².
So I = 6.25 kg m².
omega = 60 rev/min = 60 × 2π/60 = 2π rad/s ≈ 6.283. L = I × omega = 6.25 × 6.283 ≈ 39.3 kg m²/s.
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