alleryTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis through center perpendicular to rod:
A48
B36
C24
D12
Answer & Solution
Correct answer: C. 24
Each mass at distance 2 m from center.
We have I = sum m × r².
That is I = 3 × 2² + 3 × 2².
That is I = 12 + 12.
So I = 24 kg m².
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