The mole fraction of ethylene glycol in a 20 % (w/w) aqueous solution (molar masses: glycol 62, water 18) is closest to
- 0.068
- 0.032
- 0.100
- 0.150
Show answer and solution
Correct answer: A. 0.068
1. Consider 100 g of solution: 20 g glycol + 80 g water.
2. Moles of glycol = 20 / 62 = 0.322 mol.
3. Moles of water = 80 / 18 = 4.444 mol.
4. x_glycol = 0.322 / (0.322 + 4.444) = 0.068.
_Source: syllabus Chemistry, Unit 1 "Solutions", Example 1.1_