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The mole fraction of ethylene glycol in a 20 % (w/w) aqueous solution (molar masses: glycol 62, water 18) is closest to

A0.068
B0.032
C0.100
D0.150
Answer & Solution
Correct answer: A. 0.068
1. Consider 100 g of solution: 20 g glycol + 80 g water. 2. Moles of glycol = 20 / 62 = 0.322 mol. 3. Moles of water = 80 / 18 = 4.444 mol. 4. x_glycol = 0.322 / (0.322 + 4.444) = 0.068. _Source: syllabus Chemistry, Unit 1 "Solutions", Example 1.1_
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