Which of these solutions will boil at the highest temperature at 1 atm?

Question

Accepted Answer

B. {'text': '0.1 m Na₂SO₄', 'label': 'B'}

1. Boiling point elevation ΔT_b = K_b × m × i (with i the van't Hoff factor).
2. For glucose i = 1; for NaCl i ≈ 2; for Na₂SO₄ i ≈ 3 (dissociates into 2 Na⁺ + SO₄²⁻).
3. So Na₂SO₄ gives the largest ΔT_b at the same molality.
4. Higher elevation means a higher observed boiling point at 1 atm.
_Source: NCERT Class 12 Chemistry, Unit 1 "Solutions", §1.6_

Answer

{'text': '0.1 m glucose', 'label': 'A'}

Answer

{'text': '0.1 m NaCl', 'label': 'C'}

Answer

{'text': 'Pure water', 'label': 'D'}