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Indian Navy Pilot Structure of Atom — practice questions

Explore 41 free Structure of Atom questions in Indian Navy Pilot Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Structure of Atom questions and exercises with answers

Showing questions 1–30 of 41.

The radius of the $n$-th Bohr orbit of a hydrogen-like atom of atomic number $Z$ varies as:Read the answer and worked solution →Number of orbitals in subshell of azimuthal quantum number l:Read the answer and worked solution →For hydrogen, wavelength emitted in n=3 to n=2 transition (Balmer):Read the answer and worked solution →de Broglie wavelength of an electron with momentum p:Read the answer and worked solution →Number of subshells in shell with n = 3:Read the answer and worked solution →Rutherford's $\alpha$-particle scattering experiment used a thin foil of which metal?Read the answer and worked solution →For a hydrogen-like atom of nuclear charge $Z$, the radius of the $n$th Bohr orbit scales asRead the answer and worked solution →The energy of the $n$th Bohr orbit of a hydrogen-like atom isRead the answer and worked solution →An electron is accelerated through a potential difference of $100\,V$. Its de Broglie wavelength is approximatelyRead the answer and worked solution →How many orbitals are present in the $n = 3$ shell?Read the answer and worked solution →In Thomson's atomic model (plum-pudding), the atom isRead the answer and worked solution →The Bohr orbit velocity of the ground-state electron in hydrogen is aboutRead the answer and worked solution →As per your syllabus, which pair of nuclides represents ISOBARS (same A, different Z)?Read the answer and worked solution →As per your syllabus, eqn 2.22, the de Broglie wavelength λ of a particle of momentum p (or mass m, velocity v) is which expression?Read the answer and worked solution →The shape of a p-orbital is best described as:Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →

Worked practice questions

The radius of the $n$-th Bohr orbit of a hydrogen-like atom of atomic number $Z$ varies as:

  1. $r \propto n / Z^2$
  2. $r \propto Z / n^2$
  3. $r \propto n^2 / Z$
  4. $r \propto Z n^2$
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Correct answer: C. $r \propto n^2 / Z$

From Bohr's derivation, $r_n = \dfrac{n^2 h^2}{4\pi^2 m k Z e^2}$, hence $r_n \propto n^2 / Z$. **Therefore higher orbits are larger ($n^2$) and higher-$Z$ atoms hold their electrons in tighter orbits ($1/Z$).**

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Number of orbitals in subshell of azimuthal quantum number l:

  1. l² + 1
  2. l+1
  3. 2l+1
  4. l
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Correct answer: C. 2l+1

For given l, m_l takes values -l, -l+1, ..., 0, ..., l-1, l → that's 2l+1 values. So 2l+1 orbitals. For s (l=0): 1 orbital. For p (l=1): 3 orbitals. For d (l=2): 5 orbitals.

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For hydrogen, wavelength emitted in n=3 to n=2 transition (Balmer):

  1. Lyman alpha at 121 nm
  2. UV at 100 nm
  3. Balmer alpha at 656 nm (red, in visible)
  4. IR at 1875 nm
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Correct answer: C. Balmer alpha at 656 nm (red, in visible)

**Balmer series:** transitions ending at n=2. n=3 to 2 is Hα (Balmer alpha), wavelength 656 nm (red, visible). The red color of hydrogen plasma comes from this line.

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