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As per your syllabus, eqn 2.22, the de Broglie wavelength λ of a particle of momentum p (or mass m, velocity v) is which expression?
Aλ = m v / h
Bλ = h / (m v) = h / p
Cλ = h × m × v
Dλ = h × p
Answer & Solution
Correct answer: B. λ = h / (m v) = h / p
As per your syllabus, eqn 2.22, λ = h/p (de Broglie 1924).
Confirmed experimentally by electron diffraction.
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