For hydrogen, wavelength emitted in n=3 to n=2 transition (Balmer):
ALyman alpha at 121 nm
BUV at 100 nm
CBalmer alpha at 656 nm (red, in visible)
DIR at 1875 nm
Answer & Solution
Correct answer: C. Balmer alpha at 656 nm (red, in visible)
**Balmer series:** transitions ending at n=2. n=3 to 2 is Hα (Balmer alpha), wavelength 656 nm (red, visible).
The red color of hydrogen plasma comes from this line.
Keep practising Unit 1B1: Atomic Structure & Quantum Mechanics
Browse all Unit 1B1: Atomic Structure & Quantum Mechanics questions for JEE Advanced, or explore more Chemistry topics.
Related questions
Which Bohr orbit energy is higher (less negative)?Photoelectric effect: when light of frequency ν falls on a metal of work function φ, KE ofFor Bohr's hydrogen-like atom, what is the velocity of electron in n-th orbit (in terms ofNumber of nodes in a 3p orbital (n=3, l=1):Energy of the photon emitted in a hydrogen transition from n=4 to n=2:The Pauli exclusion principle states that two electrons in an atom cannot have:For He⁺ ion (1 electron, Z = 2), energy in ground state:Effective nuclear charge Z_eff for the 2p electron of carbon (using Slater's rules approxi