For hydrogen, wavelength emitted in n=3 to n=2 transition (Balmer):
ALyman alpha at 121 nm
BUV at 100 nm
CBalmer alpha at 656 nm (red, in visible)
DIR at 1875 nm
Answer & Solution
Correct answer: C. Balmer alpha at 656 nm (red, in visible)
Balmer series: transitions ending at n=2. n=3 to 2 is Hα (Balmer alpha), wavelength 656 nm (red, visible). The red color of hydrogen plasma comes from this line.
Related questions
An electron and a proton have the same kinetic energy. Which has the larger de Broglie wavHund's rule states that for degenerate orbitals of a subshell, electronsThe Aufbau principle states that electrons fill atomic orbitalsThe four quantum numbers (n, l, m_l, m_s) fully specify an electron in an atom. The magnetHeisenberg's uncertainty principle statesThe de Broglie wavelength associated with a particle of mass m and velocity v isFor a hydrogen-like ion of atomic number Z, the energy of the nth level isThe relationship E = hν (Planck) between photon energy and frequency contains constant h t