Number of orbitals in subshell of azimuthal quantum number l:
Al² + 1
Bl+1
C2l+1
Dl
Answer & Solution
Correct answer: C. 2l+1
For given l, m_l takes values -l, -l+1, ..., 0, ..., l-1, l → that's 2l+1 values. So 2l+1 orbitals. For s (l=0): 1 orbital. For p (l=1): 3 orbitals. For d (l=2): 5 orbitals.
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