alleryAn electron is accelerated through a potential difference of $100\,V$. Its de Broglie wavelength is approximately
A$1.23\,Å$
B$12.3\,Å$
C$0.0123\,Å$
D$0.123\,Å$
Answer & Solution
Correct answer: A. $1.23\,Å$
For an electron accelerated through $V$ volts, $\lambda = \dfrac{12.27}{\sqrt{V}}\,Å$.
With $V = 100$: $\lambda = 12.27/10 \approx 1.23\,Å$.
This is comparable to atomic spacings — basis of electron diffraction.
Keep practising Structure of Atom
Browse all Structure of Atom questions for AP Intermediate 1st Year, or explore more Chemistry topics.
Related questions
NEET · Chemistry · Quantum NumbersIn the photoelectric effect, the kinetic energy of ejected electrons is:The electronic configuration of Cr (Z=24) is an exception, written as:By the AUFBAU principle, the 3d subshell starts filling:Hund's rule states that electrons in degenerate orbitals:Heisenberg's uncertainty principle is most accurately stated as:The de Broglie wavelength of a particle with momentum p is:The energy of the nth orbit in a hydrogen atom (Bohr's model) is: