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An electron is accelerated through a potential difference of $100\,V$. Its de Broglie wavelength is approximately
A$1.23\,Å$
B$12.3\,Å$
C$0.0123\,Å$
D$0.123\,Å$
Answer & Solution
Correct answer: A. $1.23\,Å$
For an electron accelerated through $V$ volts, $\lambda = \dfrac{12.27}{\sqrt{V}}\,Å$. With $V = 100$: $\lambda = 12.27/10 \approx 1.23\,Å$. This is comparable to atomic spacings — basis of electron diffraction.
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