alleryde Broglie wavelength of an electron with momentum p:
Aλ = h / p
Bλ = p / h
Cλ = h × p
Dλ = h c / p
Answer & Solution
Correct answer: A. λ = h / p
de Broglie: λ = h/p.
Every particle has wavelike properties with wavelength inversely proportional to momentum.
For macroscopic objects (large p), λ is unmeasurably small.
For electrons, λ is comparable to atomic dimensions.
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