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Indian Navy Pilot Alkenes — practice questions

Explore 61 free Alkenes questions in Indian Navy Pilot Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Alkenes questions and exercises with answers

Showing questions 1–30 of 61.

The radius of the $n$-th Bohr orbit of a hydrogen-like atom of atomic number $Z$ varies as:Read the answer and worked solution →As per your syllabus, + Fig 9.1, the H-C-H bond angle in methane and the carbon hybridisation are which?Read the answer and worked solution →As per your syllabus, the rate of substitution of HYDROGENS in alkane halogenation goes in which order (by carbon class)?Read the answer and worked solution →As per your syllabus, partial reduction of an alkyne to a CIS alkene uses which catalyst?Read the answer and worked solution →As per your syllabus, addition of water to propyne under HgSO₄/H₂SO₄ gives mainly which product (Markovnikov)?Read the answer and worked solution →As per your syllabus, the carbon atoms of benzene are which hybridisation?Read the answer and worked solution →As per your syllabus, nitration, the actual ELECTROPHILE that attacks benzene in HNO₃ + H₂SO₄ mixture is which species?Read the answer and worked solution →As per your syllabus, Friedel-Crafts ACYLATION of benzene uses an acyl halide + AlCl₃ to generate which electrophile?Read the answer and worked solution →As per your syllabus, halogens (-Cl, -Br) on benzene are which kind of directors despite their deactivating -I effect?Read the answer and worked solution →Which trend is followed by ionisation energy across a period?Read the answer and worked solution →Three elements B, Si and Ge areRead the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Which principle is being described?Read the answer and worked solution →

Worked practice questions

The radius of the $n$-th Bohr orbit of a hydrogen-like atom of atomic number $Z$ varies as:

  1. $r \propto n / Z^2$
  2. $r \propto Z / n^2$
  3. $r \propto n^2 / Z$
  4. $r \propto Z n^2$
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Correct answer: C. $r \propto n^2 / Z$

From Bohr's derivation, $r_n = \dfrac{n^2 h^2}{4\pi^2 m k Z e^2}$, hence $r_n \propto n^2 / Z$. **Therefore higher orbits are larger ($n^2$) and higher-$Z$ atoms hold their electrons in tighter orbits ($1/Z$).**

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As per your syllabus, + Fig 9.1, the H-C-H bond angle in methane and the carbon hybridisation are which?

  1. 180° and sp
  2. 109.5° and sp³
  3. 104.5° and sp³
  4. 120° and sp²
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Correct answer: B. 109.5° and sp³

Your syllabus: methane has tetrahedral geometry, sp³ carbon, all H-C-H bond angles 109.5°.

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As per your syllabus, the rate of substitution of HYDROGENS in alkane halogenation goes in which order (by carbon class)?

  1. 2° > 3° > 1°
  2. 1° > 2° > 3°
  3. All equal
  4. 3° > 2° > 1°
Show answer and solution

Correct answer: D. 3° > 2° > 1°

Your syllabus: 3° > 2° > 1° (matches free-radical stability — tertiary radical is most stable).

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