The radius of the $n$-th Bohr orbit of a hydrogen-like atom of atomic number $Z$ varies as:
- $r \propto n / Z^2$
- $r \propto Z / n^2$
- $r \propto n^2 / Z$
- $r \propto Z n^2$
Show answer and solution
Correct answer: C. $r \propto n^2 / Z$
From Bohr's derivation, $r_n = \dfrac{n^2 h^2}{4\pi^2 m k Z e^2}$, hence $r_n \propto n^2 / Z$.
**Therefore higher orbits are larger ($n^2$) and higher-$Z$ atoms hold their electrons in tighter orbits ($1/Z$).**