alleryWater flows through pipe area A₁ = 4 cm² at 2 m/s, narrows to A₂ = 1 cm². Velocity at narrow section:
A0.5 m/s
B2 m/s
C8 m/s (A₁v₁ = A₂v₂ → v₂ = 4 × 2 = 8)
D16 m/s
Answer & Solution
Correct answer: C. 8 m/s (A₁v₁ = A₂v₂ → v₂ = 4 × 2 = 8)
**Continuity:** A₁v₁ = A₂v₂.
We have v₂ = (A₁/A₂) v₁.
That is v₂ = 4 × 2.
So v₂ = 8 m/s.
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