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Compressibility (1/B) of water at standard conditions:
A10⁻¹⁸
B1 Pa⁻¹
CCannot determine
DAbout 4.6 × 10⁻¹⁰ Pa⁻¹ (B ≈ 2.2 × 10⁹ Pa)
Answer & Solution
Correct answer: D. About 4.6 × 10⁻¹⁰ Pa⁻¹ (B ≈ 2.2 × 10⁹ Pa)
Water bulk modulus B ≈ 2.2 GPa. Compressibility = 1/B ≈ 4.6 × 10⁻¹⁰ Pa⁻¹. Means 1 atm causes ~5 × 10⁻⁵ volume change. Water is nearly incompressible — hence assumption valid in hydraulics.
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