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For dynamic surface tension in oil drop slowly forming at tip of pipette, drop falls when:

ADrop weight = 1
BDrop weight ≥ surface tension force (= γ × circumference)
CRandom
DAlways falls
Answer & Solution
Correct answer: B. Drop weight ≥ surface tension force (= γ × circumference)
Drop hangs by surface tension force γ × 2πr until weight exceeds it: mg = γ × 2πr → drop falls. Used in stalagmometer to measure surface tension by counting drops/volume.
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