alleryFor thin spherical shell of water (radius R, thickness t), volume of water:
Aπ R²
BV = 0
C(4/3)π R³
D≈ 4π R² t (for t << R, approximate via differential)
Answer & Solution
Correct answer: D. ≈ 4π R² t (for t << R, approximate via differential)
dV/dR = 4πR² (surface area).
Thin shell V ≈ 4πR² × t for t << R. Useful in fluid dynamics, atomic structure (shell-by-shell electron density).
Keep practising Unit 2A: Newton's Laws and Translational Equilibrium
Browse all Unit 2A: Newton's Laws and Translational Equilibrium questions for AP Physics 1, or explore more Physics topics.
Related questions
At what temperature does kT equal 1 eV?A car travels 100 km at 50 km/h, then 100 km at 100 km/h. Average speed:Photon of wavelength 200 nm strikes metal with work function 2 eV. KE of fastest photoelecWork done in stretching wire by 1 mm is W. Work to stretch it by 2 mm (same wire, within eMagnetic flux through a coil changes from 5 mWb to 1 mWb in 0.1 s. Induced EMF:Bohr radius for hydrogen is 0.53 Å. Radius of 3rd orbit:Two coherent sources of intensity I and 4I interfere. Maximum intensity in resulting patteFor a body in SHM with amplitude A, at displacement x, ratio of KE to total energy: