Start learning →

For elastic potential energy in stretched wire: F × ΔL / 2. Also equals:

AForce × length
BAll same
CF × ΔL
D(1/2) × stress × strain × volume
Answer & Solution
Correct answer: D. (1/2) × stress × strain × volume
PE = (1/2) F ΔL. **Per unit volume:** u = (1/2) σ ε = (1/2)(F/A)(ΔL/L). **Total:** u × (A × L) = (1/2) F ΔL. ✓
Practise this question with Quill — AP Physics 1 →

Keep practising Unit 2A: Newton's Laws and Translational Equilibrium

Browse all Unit 2A: Newton's Laws and Translational Equilibrium questions for AP Physics 1, or explore more Physics topics.

Start a Unit 2A: Newton's Laws and Translational Equilibrium lesson →