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For elastic potential energy in stretched wire: F × ΔL / 2. Also equals:
AForce × length
BAll same
CF × ΔL
D(1/2) × stress × strain × volume
Answer & Solution
Correct answer: D. (1/2) × stress × strain × volume
PE = (1/2) F ΔL. Per unit volume: u = (1/2) σ ε = (1/2)(F/A)(ΔL/L). Total: u × (A × L) = (1/2) F ΔL. ✓
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