Find Y if a wire of length 4 m, area 0.1 mm² stretches 0.5 mm under 5 …

Question

Find Y if a wire of length 4 m, area 0.1 mm² stretches 0.5 mm under 5 kg load (g = 10):

Accepted Answer

D. Y = 4 × 10¹² Pa

F = 50 N. A = 0.1 mm² = 10⁻⁷ m². L = 4 m, ΔL = 5 × 10⁻⁴ m. σ = F/A = 5 × 10⁸ Pa. ε = ΔL/L = 1.25 × 10⁻⁴. Y = σ/ε = 5 × 10⁸ / 1.25 × 10⁻⁴ = 4 × 10¹² Pa.

Answer

Y = 10⁹

Answer

Y = 10⁵

Answer

Y = 4 × 10¹¹ Pa (F = 50 N, σ = 50/10⁻⁷ = 5×10⁸, ε = 0.5/4000 = 1.25×10⁻⁴, Y = 4×10¹²)