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Hydraulic press: small piston area 5 cm², large piston area 50 cm². Force on small piston 20 N. Force on large:
A20 N
B2 N
C200 N (F₂ = F₁ × A₂/A₁)
D2000 N
Answer & Solution
Correct answer: C. 200 N (F₂ = F₁ × A₂/A₁)
Pascal's law: F₁/A₁ = F₂/A₂ → F₂ = 20 × (50/5) = 200 N. 10× force amplification.
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