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AP Physics 1 Unit 1C: Kinematics: Relative & Circular Motion — practice questions

Explore 92 free Unit 1C: Kinematics: Relative & Circular Motion questions in AP Physics 1 Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 1C: Kinematics: Relative & Circular Motion questions and exercises with answers

Showing questions 1–30 of 92.

A constant force does work W on a body that starts from rest. If the same force acts for twice the displacement, the kinetic energy becomes:Read the answer and worked solution →For a particle moving along a straight line under a varying force F(x), the work done from x = a to x = b is:Read the answer and worked solution →A heavy body and a light body have the same kinetic energy. The body with the greater momentum is:Read the answer and worked solution →The average power for a process is computed as:Read the answer and worked solution →The dimensional formula of power is:Read the answer and worked solution →The SI unit of the universal gravitational constant G is:Read the answer and worked solution →The approximate value of G is:Read the answer and worked solution →The acceleration due to gravity g at the Earth's surface (radius R, mass M_E) is:Read the answer and worked solution →Variation of g with height h above the Earth's surface (for h ≪ R) is approximately:Read the answer and worked solution →At a depth d below the Earth's surface (assuming uniform density), g varies as:Read the answer and worked solution →The value of g at the centre of a uniform spherical Earth is:Read the answer and worked solution →Kepler's first law (orbits) states that planetary orbits are:Read the answer and worked solution →Kepler's second law states that the line joining a planet to the Sun sweeps out:Read the answer and worked solution →Kepler's third law gives the relation T² ∝ ___, where T is the orbital period and a the semi-major axis:Read the answer and worked solution →The gravitational potential energy of a two-particle system separated by r (taking U → 0 as r → ∞) is:Read the answer and worked solution →The orbital speed of a satellite in a circular orbit of radius r around a planet of mass M is:Read the answer and worked solution →The escape speed from the surface of a planet of mass M and radius R is:Read the answer and worked solution →The escape speed at the Earth's surface is approximately:Read the answer and worked solution →The orbital speed of a satellite in a low Earth orbit (just above the surface) is approximately:Read the answer and worked solution →For a satellite, escape speed v_e and orbital speed v_o (at the same height) are related by:Read the answer and worked solution →A geostationary satellite orbits the Earth with a period of approximately:Read the answer and worked solution →A geostationary satellite stays above the:Read the answer and worked solution →For a satellite in a circular orbit, total mechanical energy E and kinetic energy K are related by:Read the answer and worked solution →The gravitational field inside a uniform spherical shell of mass is:Read the answer and worked solution →For points outside a spherically symmetric body, gravitational attraction is as if all mass were concentrated at the:Read the answer and worked solution →The gravitational potential V at a point at distance r from a point mass M is:Read the answer and worked solution →At a great distance from the Earth, the gravitational potential approaches:Read the answer and worked solution →The path of a projectile launched from Earth with a speed equal to escape velocity (radially, ignoring air drag) is:Read the answer and worked solution →If the radius of a planet doubles while its mass stays the same, g at its surface becomes:Read the answer and worked solution →Two satellites orbit a planet at radii r and 4r in circular orbits. The ratio of their periods T1 : T2 is:Read the answer and worked solution →

Worked practice questions

A constant force does work W on a body that starts from rest. If the same force acts for twice the displacement, the kinetic energy becomes:

  1. 2W
  2. W
  3. W/2
  4. 4W
Show answer and solution

Correct answer: A. 2W

W = F·s; doubling s with same F doubles work and hence KE (starting from rest).

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For a particle moving along a straight line under a varying force F(x), the work done from x = a to x = b is:

  1. F(b)−F(a)
  2. F(a)·(b−a)
  3. F(b)·(b−a)
  4. ∫_a^b F(x) dx
Show answer and solution

Correct answer: D. ∫_a^b F(x) dx

Work = area under F–x curve.

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A heavy body and a light body have the same kinetic energy. The body with the greater momentum is:

  1. the lighter one
  2. the heavier one
  3. both have equal momentum
  4. cannot be determined
Show answer and solution

Correct answer: B. the heavier one

p = √(2mK); for fixed K, p ∝ √m, so heavier ⇒ larger momentum.

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More Physics topics

Unit 8: Fluids: Density, Buoyancy and ContinuityUnit 1B: Kinematics: 2D Motion & ProjectilesUnit 2A: Newton's Laws and Translational EquilibriumUnit 2B: Friction, Gravitational and Normal ForcesUnit 3A: Work and Kinetic Energy TheoremUnit 3B: Potential Energy & Conservation of EnergyUnit 4A: Linear Momentum and ImpulseUnit 4B: Conservation of Linear Momentum & Collisions