A particle has SHM with x = A cos(ωt). At t = 0, the particle is at:
Ax = A/2
BRandom
Cx = A (extreme position, v = 0)
Dx = 0 with maximum velocity
Answer & Solution
Correct answer: C. x = A (extreme position, v = 0)
At t = 0: x = A cos(0) = A. So particle starts from extreme position (x = A). Velocity v = -Aω sin(ωt), at t=0 is 0. Particle starts from rest at maximum displacement.
Related questions
A particle of mass 0.2 kg performs S.H.M. of amplitude 0.05 m with period π s. Its maximumIn damped harmonic motion, the amplitude of oscillationTwo springs of force constants k₁ and k₂ are connected in series and stretched by an exterA particle in S.H.M. of period 2 s starts from rest at the extreme position. Its displacemThe kinetic energy of a particle of mass m in linear S.H.M. of amplitude A at displacementA simple pendulum of length 1 m on the earth's surface (g = π² m/s²) has periodA spring-mass system of mass m and spring constant k oscillates with periodA particle executes S.H.M. with amplitude A and angular frequency ω. Its maximum accelerat