A mass m on a vertical spring of constant k. The equilibrium extension is x0 = mg/k. The mass is set into SHM. Frequency depends on:
AOnly g
Bm, k, and g
Cm and k only
DOnly x0
Answer & Solution
Correct answer: C. m and k only
f = (1/(2π))√(k/m). g determines equilibrium position x0, not the oscillation frequency. SHM about equilibrium has same frequency as on horizontal frictionless surface.
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