The escape speed from the surface of a planet of mass M and radius R is:
A√(GM/R)
BGM/R
C√(GM/R²)
D√(2GM/R)
Answer & Solution
Correct answer: D. √(2GM/R)
v_esc = √(2GM/R).
Related questions
A ball is projected upwards from a height $h$ above the surface of the earth with velocityA ball is thrown vertically upwards. Which of the following graph/graphs represent velocitA stone projected with a velocity $u$ at an angle $\theta$ with the horizontal reaches maxA block $P$ of mass $m$ is placed on a frictionless horizontal surface. Another block $Q$ The potential energy between two atoms in a molecule is given by $U(x) = \frac{a}{x^{1/2}}A particle which is constrained to move along the $x$-axis, is subjected to a force in theTwo particles of masses $m_1$ and $m_2$ in projectile motion have velocities $\vec{u}_1$ aA thin uniform circular disc of mass $M$ and radius $R$ is rotating in a horizontal plane