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SAIL Management Trainee Time and Work — practice questions

Explore 41 free Time and Work questions in SAIL Management Trainee Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

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Time and Work questions and exercises with answers

Showing questions 1–30 of 41.

If 3/5th of a cistern is filled in 1 minute, how much more time is required to fill the rest of it?Read the answer and worked solution →Pipes A and B can fill a tank in X minutes and 6 minutes respectively. Together they fill it in 1.5 minutes. Find X.Read the answer and worked solution →10 men can finish painting a wall in 8 days. How many more men are needed to finish the same work in 4 days?Read the answer and worked solution →A pipe can fill a tank in 15 hours. Due to a leak at the bottom, it takes 20 hours to fill. If the tank is full, in how much time will the leak empty it?Read the answer and worked solution →If 200 men can construct a building in 1024 days, how many men are needed to construct the same building in 256 days?Read the answer and worked solution →Trij can paint a wall alone in 7.2 days while Madhu takes 10.8 days for the same work. Working together, how many days will they take to paint 5/6 of the wall?Read the answer and worked solution →Rohan and Rohit together can finish a job in 10 days, while Rohan alone can do it in 15 days. In how many days can Rohit alone finish the job?Read the answer and worked solution →Complete the rule for workers and timeRead the answer and worked solution →True or false: workers and timeRead the answer and worked solution →Scaling the workforceRead the answer and worked solution →Rises or falls as the workforce grows?Read the answer and worked solution →Order the steps: a time and work questionRead the answer and worked solution →Assertion and reason: workers and timeRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Tap every situation that behaves like time and workRead the answer and worked solution →Reading a time and work setupRead the answer and worked solution →True or false: sharing a fixed jobRead the answer and worked solution →Which equation, and why?Read the answer and worked solution →Flip and pair: situation with proportionRead the answer and worked solution →Spot the odd one outRead the answer and worked solution →Complete the constant for a fixed jobRead the answer and worked solution →Scaling a workforce, harder casesRead the answer and worked solution →Does this change the total work, or only the time?Read the answer and worked solution →True or false: worker-daysRead the answer and worked solution →Order the reasoning: why more hands finish soonerRead the answer and worked solution →Assertion and reason: sharing the workRead the answer and worked solution →Complete the two-way ruleRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Tap every quantity that stays fixed in a time and work problemRead the answer and worked solution →

Worked practice questions

If 3/5th of a cistern is filled in 1 minute, how much more time is required to fill the rest of it?

  1. 30 sec
  2. 36 sec
  3. 40 sec
  4. 24 sec
Show answer and solution

Correct answer: C. 40 sec

1. In 1 minute (60 sec) the rate fills 3/5 of the cistern. 2. The remaining part is 1 − 3/5 = 2/5 of the cistern. 3. Time for 2/5 = (2/5) ÷ (3/5) × 60 sec = (2/3) × 60 = 40 sec. _Source: RRB Group D (RRC) PYQ, held 27-10-2013, Q.42._

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Pipes A and B can fill a tank in X minutes and 6 minutes respectively. Together they fill it in 1.5 minutes. Find X.

  1. 1 minute
  2. 4 minutes
  3. 5 minutes
  4. 2 minutes
Show answer and solution

Correct answer: D. 2 minutes

1. Combined rate: 1/X + 1/6 = 1/1.5 = 2/3. 2. 1/X = 2/3 - 1/6 = 4/6 - 1/6 = 3/6 = 1/2. 3. So X = 2 minutes. _Source: RRB Group D CEN-02/2018 PYQ, Q.20._

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10 men can finish painting a wall in 8 days. How many more men are needed to finish the same work in 4 days?

  1. 10
  2. 8
  3. 5
  4. 20
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Correct answer: A. 10

1. Total work = 10 x 8 = 80 man-days. 2. To finish in 4 days, men needed = 80 / 4 = 20. 3. Extra men = 20 - 10 = 10. _Source: RRB Group D CEN-02/2018 PYQ, Q.63._

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