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MP Board Class 12 (MPBSE) Alcohols, Phenols and Ethers — practice questions

Explore 14 free Alcohols, Phenols and Ethers questions in MP Board Class 12 (MPBSE) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Alcohols, Phenols and Ethers questions and exercises with answers

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Worked practice questions

Phenol is more acidic than ethanol because:

  1. Phenol has a stronger O-H bond than ethanol always
  2. The phenoxide ion is stabilised by aromatic resonance
  3. Ethanol is fully covalent while phenol is ionic in nature
  4. Phenol is heavier so it dissociates more in water always
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Correct answer: B. The phenoxide ion is stabilised by aromatic resonance

Phenoxide ion's negative charge is delocalised into the benzene ring, stabilising it phenol's $pK_a \approx 10$, ethanol's $\approx 16$.

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The Williamson ether synthesis works best with:

  1. A primary alkyl halide and a sodium alkoxide as nucleophile
  2. A tertiary alkyl halide and a sodium alkoxide for SN2 reaction
  3. A secondary alkyl halide and water as the only nucleophile
  4. A primary alkyl halide and aqueous KOH at high pressure
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Correct answer: A. A primary alkyl halide and a sodium alkoxide as nucleophile

SN2 mechanism: primary R-X is least hindered with alkoxide nucleophile it gives the ether cleanly.

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An ALCOHOL in which the $\mathrm{-OH}$ group is attached to a carbon bonded to ONE other alkyl group is classified as

  1. primary (1°)
  2. secondary (2°)
  3. tertiary (3°)
  4. quaternary (4°)
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Correct answer: A. primary (1°)

1. syllabus classifies alcohols by the substitution at the carbon bearing the $\mathrm{-OH}$ group. 2. PRIMARY (1°): the $\mathrm{C{-}OH}$ carbon is attached to ONE other carbon (one alkyl group). Example: ethanol $\mathrm{CH_3CH_2OH}$. 3. SECONDARY (2°): attached to TWO other carbons. Example: propan-2-ol $\mathrm{(CH_3)_2CHOH}$. 4. TERTIARY (3°): attached to THREE other carbons. Example: $\mathrm{(CH_3)_3COH}$ (tert-butanol). 5. There is no QUATERNARY (4°) alcohol — that would require 4 carbons attached, leaving no room for $\mathrm{-OH}$. 6. Other options describe higher substitution patterns not matching the stated single-alkyl case. _Source: syllabus Chemistry Part 2, Ch 7 "Alcohols, Phenols and Ethers", §7.1.1 (Classification of alcohols), p. 1–2._

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