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MP Board Class 12 (MPBSE) Alcohols Phenols Ethers — practice questions

Explore 40 free Alcohols Phenols Ethers questions in MP Board Class 12 (MPBSE) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Alcohols Phenols Ethers questions and exercises with answers

Showing questions 1–30 of 40.

Phenol is more acidic than ethanol because:Read the answer and worked solution →The Williamson ether synthesis works best with:Read the answer and worked solution →An ALCOHOL in which the $\mathrm{-OH}$ group is attached to a carbon bonded to ONE other alkyl group is classified asRead the answer and worked solution →The IUPAC name of $\mathrm{(CH_3)_2CHOH}$ isRead the answer and worked solution →The reaction of ethanol with sodium metal producesRead the answer and worked solution →The acidity (Brønsted acidity) order of the following isRead the answer and worked solution →Ethanol heated with concentrated $\mathrm{H_2SO_4}$ at $443\,\text{K}$ (170°C) gives mainlyRead the answer and worked solution →The WILLIAMSON ETHER SYNTHESIS prepares ethers by reactingRead the answer and worked solution →The REIMER-TIEMANN reaction converts phenol to salicylaldehyde. The reagents areRead the answer and worked solution →Phenol reacts with bromine WATER (aqueous $\mathrm{Br_2}$) at room temperature to giveRead the answer and worked solution →Ethanol reacts with $\mathrm{PCl_5}$ to give which set of products?Read the answer and worked solution →The KOLBE reaction converts phenol (in the form of sodium phenoxide) into salicylic acid. The conditions and key reagent areRead the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →

Worked practice questions

Phenol is more acidic than ethanol because:

  1. Phenol has a stronger O-H bond than ethanol always
  2. The phenoxide ion is stabilised by aromatic resonance
  3. Ethanol is fully covalent while phenol is ionic in nature
  4. Phenol is heavier so it dissociates more in water always
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Correct answer: B. The phenoxide ion is stabilised by aromatic resonance

Phenoxide ion's negative charge is delocalised into the benzene ring, stabilising it phenol's $pK_a \approx 10$, ethanol's $\approx 16$.

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The Williamson ether synthesis works best with:

  1. A primary alkyl halide and a sodium alkoxide as nucleophile
  2. A tertiary alkyl halide and a sodium alkoxide for SN2 reaction
  3. A secondary alkyl halide and water as the only nucleophile
  4. A primary alkyl halide and aqueous KOH at high pressure
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Correct answer: A. A primary alkyl halide and a sodium alkoxide as nucleophile

SN2 mechanism: primary R-X is least hindered with alkoxide nucleophile it gives the ether cleanly.

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An ALCOHOL in which the $\mathrm{-OH}$ group is attached to a carbon bonded to ONE other alkyl group is classified as

  1. primary (1°)
  2. secondary (2°)
  3. tertiary (3°)
  4. quaternary (4°)
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Correct answer: A. primary (1°)

1. syllabus classifies alcohols by the substitution at the carbon bearing the $\mathrm{-OH}$ group. 2. PRIMARY (1°): the $\mathrm{C{-}OH}$ carbon is attached to ONE other carbon (one alkyl group). Example: ethanol $\mathrm{CH_3CH_2OH}$. 3. SECONDARY (2°): attached to TWO other carbons. Example: propan-2-ol $\mathrm{(CH_3)_2CHOH}$. 4. TERTIARY (3°): attached to THREE other carbons. Example: $\mathrm{(CH_3)_3COH}$ (tert-butanol). 5. There is no QUATERNARY (4°) alcohol — that would require 4 carbons attached, leaving no room for $\mathrm{-OH}$. 6. Other options describe higher substitution patterns not matching the stated single-alkyl case. _Source: syllabus Chemistry Part 2, Ch 7 "Alcohols, Phenols and Ethers", §7.1.1 (Classification of alcohols), p. 1–2._

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