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MP Board Class 12 (MPBSE) Chemical Kinetics — practice questions

Explore 39 free Chemical Kinetics questions in MP Board Class 12 (MPBSE) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Chemical Kinetics questions and exercises with answers

Showing questions 1–30 of 39.

For a first-order reaction, the half-life period $t_{1/2}$ is related to the rate constant $k$ as:Read the answer and worked solution →The units of the rate constant for a zero-order reaction are:Read the answer and worked solution →A catalyst on the bench changes:Read the answer and worked solution →For rate = k[A][B]², the overall order is:Read the answer and worked solution →A first-order reaction plots linearly as:Read the answer and worked solution →Half-life of a first-order reaction is:Read the answer and worked solution →Per Arrhenius, raising T:Read the answer and worked solution →For a reaction to proceed, colliding molecules must have:Read the answer and worked solution →A catalyst:Read the answer and worked solution →The RATE CONSTANT ($k$) of a reaction isRead the answer and worked solution →For a FIRST-ORDER reaction with rate constant $k$, the half-life is given byRead the answer and worked solution →For a ZERO-ORDER reaction $A \to \text{products}$, which graph is a STRAIGHT LINE?Read the answer and worked solution →A first-order reaction has a rate constant of $k = 6.93\times 10^{-3}\,\text{s}^{-1}$ at a certain temperature. The half-life is closest toRead the answer and worked solution →Rebuild a sample from its halvesRead the answer and worked solution →Order or molecularity?Read the answer and worked solution →True or false: order and molecularityRead the answer and worked solution →Read the order off the rate lawRead the answer and worked solution →Complete the definition of orderRead the answer and worked solution →True or false: where a rate law comes fromRead the answer and worked solution →Instantaneous rate or average rate?Read the answer and worked solution →Match each symbol in the Arrhenius equation to its meaningRead the answer and worked solution →Complete the definition of activation energyRead the answer and worked solution →Tap everything that raises the rate of a reactionRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →The Arrhenius equationRead the answer and worked solution →Order the steps: find the order of a reactionRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →True or false: what kinetics studiesRead the answer and worked solution →

Worked practice questions

For a first-order reaction, the half-life period $t_{1/2}$ is related to the rate constant $k$ as:

  1. $t_{1/2} = \dfrac{2.303}{k}$
  2. $t_{1/2} = \dfrac{0.693}{k}$
  3. $t_{1/2} = \dfrac{[A]_0}{2k}$
  4. $t_{1/2} = \dfrac{1}{k[A]_0}$
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Correct answer: B. $t_{1/2} = \dfrac{0.693}{k}$

For a first-order reaction $k = \dfrac{2.303}{t}\log\dfrac{[A]_0}{[A]}$. Setting $[A] = [A]_0/2$ at $t = t_{1/2}$ gives $k t_{1/2} = \ln 2 = 0.693$, hence $t_{1/2} = 0.693/k$. Option B is the zero-order expression option C is the second-order one.

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The units of the rate constant for a zero-order reaction are:

  1. $\text{mol}\,L^{-1}\,s^{-1}$
  2. $L^2\,\text{mol}^{-2}\,s^{-1}$
  3. $L\,\text{mol}^{-1}\,s^{-1}$
  4. $s^{-1}$
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Correct answer: A. $\text{mol}\,L^{-1}\,s^{-1}$

Units of $k$ for an $n$-th order reaction are $\text{mol}^{1-n}\,L^{n-1}\,s^{-1}$. Putting $n=0$ gives $\text{mol}\,L^{-1}\,s^{-1}$, which is the same as the unit of rate itself, since the rate of a zero-order reaction is independent of concentration.

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A catalyst on the bench changes:

  1. The equilibrium constant, shifting K by a known factor
  2. The position of equilibrium toward products only at start
  3. The activation energy and rate, without shifting equilibrium
  4. The standard Gibbs energy of the reaction permanently shifts
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Correct answer: C. The activation energy and rate, without shifting equilibrium

A catalyst lowers $E_a$ and speeds both forward and reverse rates equally equilibrium is unchanged.

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