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JEE Main Unit 4D: Organic Reaction Mechanisms & Techniques — practice questions

Explore 15 free Unit 4D: Organic Reaction Mechanisms & Techniques questions in JEE Main Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 4D: Organic Reaction Mechanisms & Techniques questions and exercises with answers

Showing questions 1–15 of 15.

What is the IUPAC name of the compound $\mathrm{CH_2=CH-CH_2-CH_3}$?Read the answer and worked solution →According to Markovnikov's rule, the addition of HBr to propene ($\mathrm{CH_3-CH=CH_2}$) gives predominantly:Read the answer and worked solution →When propene reacts with HBr in the presence of organic peroxides, the major product is:Read the answer and worked solution →Reductive ozonolysis (O$_3$, then Zn/H$_2$O) of $2$-methylbut-$2$-ene gives:Read the answer and worked solution →Pent-$2$-ene is treated with hot, acidic KMnO$_4$. What are the products?Read the answer and worked solution →Which of the following alkenes exhibits geometrical (cis–trans) isomerism?Read the answer and worked solution →The repeating structural unit in a polymer is called:Read the answer and worked solution →Natural rubber is a polymer of:Read the answer and worked solution →PVC (polyvinyl chloride) is obtained from:Read the answer and worked solution →Teflon is a polymer of:Read the answer and worked solution →Buna-N is a copolymer of:Read the answer and worked solution →A polymer that softens on heating and hardens on cooling reversibly is called:Read the answer and worked solution →PMMA (Plexiglas / Lucite) is made from:Read the answer and worked solution →Sort: SN1 favoured or SN2 favoured?Read the answer and worked solution →Spot the error in the IUPAC nameRead the answer and worked solution →

Worked practice questions

What is the IUPAC name of the compound $\mathrm{CH_2=CH-CH_2-CH_3}$?

  1. But-1-ene
  2. But-2-ene
  3. Butyne
  4. Butane
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Correct answer: A. But-1-ene

A four-carbon chain with a double bond starting at C1 is but-1-ene. Butyne would have a triple bond but-2-ene has the double bond between C2 and C3.

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According to Markovnikov's rule, the addition of HBr to propene ($\mathrm{CH_3-CH=CH_2}$) gives predominantly:

  1. propane
  2. $1{,}2$-dibromopropane
  3. $2$-bromopropane
  4. $1$-bromopropane
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Correct answer: C. $2$-bromopropane

**Markovnikov's rule:** the H of HX attaches to the carbon of the double bond bearing more hydrogens, leaving X on the more substituted carbon. Here Br goes to C2 → 2-bromopropane.

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When propene reacts with HBr in the presence of organic peroxides, the major product is:

  1. propan-$1$-ol
  2. propane
  3. $2$-bromopropane
  4. $1$-bromopropane
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Correct answer: D. $1$-bromopropane

Peroxides switch the mechanism from ionic to free-radical (peroxide / Kharasch effect). The radical adds anti-Markovnikov so Br lands on the *less* substituted carbon — giving 1-bromopropane. The trap is option B (Markovnikov product) — that's the answer without peroxides. The peroxide effect is specific to HBr HCl and HI do not show it.

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