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JEE Main Chemical Thermodynamics — practice questions

Explore 7 free Chemical Thermodynamics questions in JEE Main Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Chemical Thermodynamics questions and exercises with answers

Showing questions 1–7 of 7.

The atomic number Z of an element is defined asRead the answer and worked solution →The radius of the nth Bohr orbit of hydrogen is proportional toRead the answer and worked solution →The energy of the electron in the nth Bohr orbit of hydrogen isRead the answer and worked solution →The maximum wavelength in the Lyman series of the hydrogen spectrum (transition n₂ → 1) corresponds to n₂ =Read the answer and worked solution →Which series of the hydrogen spectrum lies in the visible region?Read the answer and worked solution →The relationship E = hν (Planck) between photon energy and frequency contains constant h that is approximatelyRead the answer and worked solution →For a hydrogen-like ion of atomic number Z, the energy of the nth level isRead the answer and worked solution →

Worked practice questions

The atomic number Z of an element is defined as

  1. Number of protons in the nucleus
  2. Total number of protons + neutrons in the nucleus
  3. Number of electrons in the outermost shell
  4. Total mass of the atom in u
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Correct answer: A. Number of protons in the nucleus

1. Atomic number Z is a defining property of an element. 2. Z equals the number of protons in the nucleus of the atom. 3. In a neutral atom, Z also equals the number of electrons. 4. Mass number A = protons + neutrons; A − Z = neutron count. _Source: syllabus Chemistry, Ch 2 "Structure of Atom", §2.3_

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The radius of the nth Bohr orbit of hydrogen is proportional to

  1. n
  2. 1/n²
  3. 1/n
  4. n²
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Correct answer: D. n²

1. Bohr radius formula: r_n = (n² / Z) × 0.529 Å. 2. For hydrogen (Z = 1), r_n = n² × 0.529 Å. 3. So r_n is directly proportional to n² (the square of the principal quantum number). 4. Bohr radius (n = 1) is 0.529 Å; n = 2 gives 2.116 Å. _Source: syllabus Chemistry, Ch 2 "Structure of Atom", §2.4_

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The energy of the electron in the nth Bohr orbit of hydrogen is

  1. E_n = −13.6 / n² eV
  2. E_n = −13.6 × n² eV
  3. E_n = +13.6 / n² eV
  4. E_n = 13.6 × n eV
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Correct answer: A. E_n = −13.6 / n² eV

1. Bohr found E_n = −(k Z² m e⁴ / (8 ε₀² h²)) × 1/n². 2. For H atom (Z = 1), evaluating gives E_n = −13.6 / n² eV. 3. Ground state (n = 1) energy is −13.6 eV. 4. Negative sign indicates bound state; energy → 0 as n → ∞. _Source: syllabus Chemistry, Ch 2 "Structure of Atom", §2.4_

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More Chemistry topics

Aldehydes, Ketones and Carboxylic AcidsElectrochemistryStructure of AtomThe d- and f-Block Elements & Coordination CompoundsSolutionsRedox ReactionsUnit 2B1: Transition Metals & Coordination CompoundsChemical Kinetics