The radius of the nth Bohr orbit of hydrogen is proportional to
A{'text': 'n', 'label': 'A'}
B{'text': '1/n²', 'label': 'B'}
C{'text': '1/n', 'label': 'C'}
D{'text': 'n²', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': 'n²', 'label': 'D'}
1. Bohr radius formula: r_n = (n² / Z) × 0.529 Å.
2. For hydrogen (Z = 1), r_n = n² × 0.529 Å.
3. So r_n is directly proportional to n² (the square of the principal quantum number).
4. Bohr radius (n = 1) is 0.529 Å; n = 2 gives 2.116 Å.
_Source: NCERT Class 11 Chemistry, Ch 2 "Structure of Atom", §2.4_
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