Electronic configuration of Cr³⁺ (Z = 24):
- [Ar] 3d⁴
- [Ar] 3d³
- [Ar] 3d⁵
- [Ar] 3d⁵ 4s¹
Show answer and solution
Correct answer: B. [Ar] 3d³
**Cr:** [Ar] 3d⁵ 4s¹.
Cr³⁺: lose 4s and two 3d → [Ar] 3d³.
Three unpaired electrons. Paramagnetic.
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Correct answer: B. [Ar] 3d³
Correct answer: D. 0.0693/min (= ln2/10)
Correct answer: A. $3 \times 10^{8}\,m\,s^{-1}$