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Indian Navy SSR Alkenes — practice questions

Explore 57 free Alkenes questions in Indian Navy SSR Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Alkenes questions and exercises with answers

Showing questions 1–30 of 57.

Which of the following alkenes exhibits geometrical (cis–trans) isomerism?Read the answer and worked solution →As per your syllabus, Mechanism, the FIRST step of methane chlorination under sunlight is best described as which?Read the answer and worked solution →As per your syllabus, the carbon-carbon triple bond in ethyne (HC≡CH) consists of which σ/π combination?Read the answer and worked solution →As per your syllabus, which of the following groups is a META-directing substituent on benzene?Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Which principle is being described?Read the answer and worked solution →Flip and pair: symbol with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Tap every statement true of the Schrodinger modelRead the answer and worked solution →Reading the models backRead the answer and worked solution →Assertion and reason: filling orbitalsRead the answer and worked solution →True or false: shells and subshellsRead the answer and worked solution →Complete the two filling rulesRead the answer and worked solution →

Worked practice questions

Which of the following alkenes exhibits geometrical (cis–trans) isomerism?

  1. Pent-$1$-ene
  2. But-$2$-ene
  3. Propene
  4. $2$-methylpropene
Show answer and solution

Correct answer: B. But-$2$-ene

**Test.** For cis–trans isomerism each sp²-carbon of the C=C bond must carry two *different* groups. If either carbon has two of the same substituent, the two configurations are identical. - **A. 2-methylpropene** $(CH_3)_2C=CH_2$ — left carbon has two CH₃ groups → no. - **B. Propene** $CH_3CH=CH_2$ — the CH₂ end has two H → no. - **C. But-2-ene** $CH_3CH=CHCH_3$ — each sp²-C carries one CH₃ and one H → **yes**, gives cis (Z) and trans (E). - **D. Pent-1-ene** $CH_2=CHCH_2CH_2CH_3$ — terminal C has two H → no. The rule of thumb: terminal alkenes never show cis–trans internal alkenes do *only if* the two substituents on each end differ.

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As per your syllabus, Mechanism, the FIRST step of methane chlorination under sunlight is best described as which?

  1. Heterolysis of C-H bond
  2. Markovnikov addition
  3. Homolysis of Cl-Cl bond
  4. Wurtz coupling
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Correct answer: C. Homolysis of Cl-Cl bond

syllabus Mechanism (i): Cl-Cl homolysis under hν gives two Cl• free radicals. Free-radical chain mechanism.

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As per your syllabus, the carbon-carbon triple bond in ethyne (HC≡CH) consists of which σ/π combination?

  1. 1 σ + 2 π
  2. 3 σ
  3. 2 σ + 1 π
  4. 1 σ + 1 π
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Correct answer: A. 1 σ + 2 π

Your syllabus: C≡C = 1 σ (sp-sp axial) + 2 π (two perpendicular p-orbital pairs). Carbons sp hybridised, linear.

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More Chemistry topics

Organic ChemistryAlcohols Phenols EthersPolymersChemical Equilibriump-Block ElementsThe p-Block ElementsAtoms and MoleculesClassification of Elements