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Indian Navy INET Atomic Structure and Valency — practice questions

Explore 12 free Atomic Structure and Valency questions in Indian Navy INET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Atomic Structure and Valency questions and exercises with answers

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Worked practice questions

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:

  1. $3.4\,\text{eV}$
  2. $13.6\,\text{eV}$
  3. $27.2\,\text{eV}$
  4. $1.51\,\text{eV}$
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Correct answer: B. $13.6\,\text{eV}$

Ionisation energy is the energy required to take the electron from $n = 1$ to $n = \infty$. $E_\infty - E_1 = 0 - (-13.6) = 13.6\,\text{eV}$. The value $27.2\,\text{eV}$ is the magnitude of the potential energy in the ground state, not the ionisation energy.

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Electron configuration of nitrogen (Z = 7):

  1. 2s² 2p⁵
  2. 1s² 2s² 2p⁴ 3p¹
  3. 1s² 2s² 2p³
  4. 1s² 2s² 2p² 3s¹
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Correct answer: C. 1s² 2s² 2p³

**N has 7 electrons:** 1s² 2s² 2p³. The 2p³ has 3 unpaired electrons by Hund's rule (each in a separate p-orbital). Very stable half-filled state, contributing to N's special inertness.

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Number of nodes in a 3p orbital (n=3, l=1):

  1. 0
  2. 2 (n-1 total nodes; 1 angular + 1 radial)
  3. 3
  4. 1
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Correct answer: B. 2 (n-1 total nodes; 1 angular + 1 radial)

Total nodes = n - 1 = 2 for n=3. Angular nodes = l = 1 (the planar node through the nucleus). Radial nodes = n - l - 1 = 1. So 1 angular + 1 radial = 2 total nodes.

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