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Indian Navy INET JEE Main 2023 Mixed — practice questions

Explore 41 free JEE Main 2023 Mixed questions in Indian Navy INET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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JEE Main 2023 Mixed questions and exercises with answers

Showing questions 1–30 of 41.

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:Read the answer and worked solution →pH of 10⁻⁸ M HCl solution (in water):Read the answer and worked solution →Number of stereoisomers of 2-bromobutane:Read the answer and worked solution →For coordination compound [Co(NH₃)₅Cl]Br₂, total ions in solution:Read the answer and worked solution →Standard enthalpy of formation of an element in its standard state:Read the answer and worked solution →In the photoelectric effect, the kinetic energy of the ejected electron depends onRead the answer and worked solution →Rydberg's formula for the wave number of a hydrogen spectral line isRead the answer and worked solution →An electron is accelerated through a potential difference of $100\,V$. Its de Broglie wavelength is approximatelyRead the answer and worked solution →The ionisation energy of hydrogen in its ground state isRead the answer and worked solution →The Bohr radius for hydrogen ($n=1, Z=1$) is approximatelyRead the answer and worked solution →The proton was discovered through experiments involvingRead the answer and worked solution →As per your syllabus, eqn 2.15, the radius of the n-th Bohr orbit for a hydrogen-like ion (one electron, atomic number Z) scales as which expression?Read the answer and worked solution →As per your syllabus, in the hydrogen-atom spectrum the BALMER series corresponds to transitions ending in n₁ = 2 and lies in which spectral region?Read the answer and worked solution →In the photoelectric effect, the kinetic energy of ejected electrons is:Read the answer and worked solution →JEEMAIN · Chemistry · Spot the Error — Chemistry BasicsRead the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →

Worked practice questions

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:

  1. $3.4\,\text{eV}$
  2. $13.6\,\text{eV}$
  3. $27.2\,\text{eV}$
  4. $1.51\,\text{eV}$
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Correct answer: B. $13.6\,\text{eV}$

Ionisation energy is the energy required to take the electron from $n = 1$ to $n = \infty$. $E_\infty - E_1 = 0 - (-13.6) = 13.6\,\text{eV}$. The value $27.2\,\text{eV}$ is the magnitude of the potential energy in the ground state, not the ionisation energy.

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pH of 10⁻⁸ M HCl solution (in water):

  1. Less than 7
  2. 8
  3. Cannot determine
  4. Close to 7 (autoionization of water dominates at this low H⁺ concentration)
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Correct answer: A. Less than 7

At 10⁻⁸ M HCl, must include water's H⁺ from autoionization (10⁻⁷ M). Total H⁺ ≈ 10⁻⁷ + 10⁻⁸ = 1.1 × 10⁻⁷ M. pH ≈ 6.96, slightly less than 7.

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Number of stereoisomers of 2-bromobutane:

  1. 8
  2. 4
  3. 2 (one chiral center → R and S enantiomers)
  4. 1
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Correct answer: C. 2 (one chiral center → R and S enantiomers)

2-bromobutane: CH₃-CHBr-CH₂-CH₃. C2 is chiral (bonded to CH₃, Br, H, C₂H₅). 1 chiral center → 2^1 = 2 enantiomers (R, S).

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More Chemistry topics

Atomic combinationsStructure of AtomAtoms and ElementsChemical EquilibriumClass9 Atom StructureChemistryAlkenesOrganic Chemistry