alleryNumber of nodes in a 3p orbital (n=3, l=1):
A0
B2 (n-1 total nodes; 1 angular + 1 radial)
C3
D1
Answer & Solution
Correct answer: B. 2 (n-1 total nodes; 1 angular + 1 radial)
Total nodes = n - 1 = 2 for n=3. Angular nodes = l = 1 (the planar node through the nucleus).
Radial nodes = n - l - 1 = 1. So 1 angular + 1 radial = 2 total nodes.
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