Start learning →

Indian Navy INET Chemical Equilibrium — practice questions

Explore 38 free Chemical Equilibrium questions in Indian Navy INET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

Practise Chemical Equilibrium with Quill →

Chemical Equilibrium questions and exercises with answers

Showing questions 1–30 of 38.

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:Read the answer and worked solution →At 298 K, water has Kw = 10⁻¹⁴. Concentration of H+ in pure water:Read the answer and worked solution →The bond order of the oxygen molecule O₂ (by molecular orbital theory) isRead the answer and worked solution →As per your syllabus, equilibrium in a physical or chemical process is best described as which kind?Read the answer and worked solution →As per your syllabus, what is the conjugate base of the Brønsted acid HSO₄⁻?Read the answer and worked solution →As per your syllabus, the conjugate base of a STRONG acid is necessarily which kind of base?Read the answer and worked solution →As per your syllabus, addition of CH₃COONa to a solution of CH₃COOH does what to the degree of ionisation of acetic acid?Read the answer and worked solution →As per your syllabus, on DILUTING a buffer solution, what happens to the buffer pH (to first approximation)?Read the answer and worked solution →JEEMAIN · Chemistry · Spot the Error — Chemistry BasicsRead the answer and worked solution →How does metallic character change down a group?Read the answer and worked solution →Which one of the following elements exhibit maximum number of valence electrons?Read the answer and worked solution →Which of the following elements would lose an electron easily?Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →

Worked practice questions

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:

  1. $3.4\,\text{eV}$
  2. $13.6\,\text{eV}$
  3. $27.2\,\text{eV}$
  4. $1.51\,\text{eV}$
Show answer and solution

Correct answer: B. $13.6\,\text{eV}$

Ionisation energy is the energy required to take the electron from $n = 1$ to $n = \infty$. $E_\infty - E_1 = 0 - (-13.6) = 13.6\,\text{eV}$. The value $27.2\,\text{eV}$ is the magnitude of the potential energy in the ground state, not the ionisation energy.

Open this question →

At 298 K, water has Kw = 10⁻¹⁴. Concentration of H+ in pure water:

  1. 10⁻¹⁴ M
  2. 10⁻⁷ M
  3. 10⁻¹ M
  4. Variable
Show answer and solution

Correct answer: B. 10⁻⁷ M

In pure water at 25°C: H2O ⇌ H+ + OH-, Kw = [H+][OH-] = 10⁻¹⁴. Since [H+] = [OH-] in pure water: [H+]² = 10⁻¹⁴, [H+] = 10⁻⁷ M. Hence neutral pH = 7.

Open this question →

The bond order of the oxygen molecule O₂ (by molecular orbital theory) is

  1. 2
  2. 1
  3. 2.5
  4. 3
Show answer and solution

Correct answer: A. 2

MO config gives bond order = (bonding − antibonding)/2 = (8−4)/2 = 2, consistent with the O=O double bond.

Open this question →

How to practise

  1. Choose a Chemical Equilibrium question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Chemistry topics

JEE Main 2023 MixedAtomic combinationsStructure of AtomAtoms and ElementsClass9 Atom StructureChemistryAlkenesOrganic Chemistry