Rydberg's formula for the wave number of a hydrogen spectral line is
A$\bar{\nu} = R(n_1^2 - n_2^2)$
B$\bar{\nu} = R\left(\dfrac{1}{n_1} - \dfrac{1}{n_2}\right)$
C$\bar{\nu} = R\left(\dfrac{n_2}{n_1}\right)$
D$\bar{\nu} = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$
Answer & Solution
Correct answer: D. $\bar{\nu} = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$
$\bar{\nu} = R_H\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$, $n_2 > n_1$. For hydrogen, $R_H = 1.097 \times 10^7\,m^{-1}$.
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